The required equation of line parallel to given line is:[tex]y = \frac{5}{6}x-8[/tex]
Step-by-step explanation:
Given equation of line is:
[tex]y = \frac{5}{6}x+1[/tex]
As the equation of line is in slope-intercept form, the co-efficient of x s the slope
Let m1 be the slope of given line
m1= 5/6
Let m2 be the slope of new line
As the slopes of two parllel lines are equal, so
m1 = m2
m2 = 5/6
The slope intercept form is:
[tex]y= m_2x+b[/tex]
Put m2 = 5/6 in equation
[tex]y = \frac{5}{6}x+b[/tex]
Putting the point in the equation
[tex]2 = \frac{5}{6}(12)+b\\2=10+b\\b = 2-10\\b = -8[/tex]
Putting the value of b, we get
[tex]y = \frac{5}{6}x-8[/tex]
Hence,
The required equation of line parallel to given line is:[tex]y = \frac{5}{6}x-8[/tex]
Keywords: Slope intercept form, equation of line
Learn more about equation of line at:
- brainly.com/question/1493255
- brainly.com/question/1491432
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