contestada

(a) A small object with mass 3.75 kg moves counterclockwise with constant speed 1.55 rad/s in a circle of radius 2.55 m centered at the origin. It starts at the point with position vector 2.55 i m. Then it undergoes an angular displacement of 8.95 rad.
(b) In what quadrant is the particle located and what angle does its position vector make with the positive x-axis?
(c) What is its velocity?

Respuesta :

Answer:3.95 m/s

Explanation:

Given

mass of object [tex]m=3.75 kg[/tex]

[tex]\omega =1.55 rad/s[/tex]

radius of circle [tex]=2.55 m[/tex]

initial Position [tex]r=2.55 \hat{i}[/tex]

angular displacement [tex]\theta _0=8.95 rad[/tex]

8.95 radian can be written as

[tex]1.42 (2\pi )[/tex]

i.e. Particle is at first quadrant with [tex]\theta =0.4242\pi \times \frac{180}{\pi }[/tex]

[tex]\theta =76.36^{\circ}[/tex]

(c)velocity is [tex]v=\omgea \times r[/tex]

[tex]v=1.55\times 2.55=3.95 m/s[/tex]

Otras preguntas