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A chemist prepares a solution of nickel(II) chloride NiCl2 by measuring out 21.μmol of nickel(II) chloride into a 200.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /mmolL of the chemist's nickel(II) chloride solution. Round your answer to 2 significant digits.

Respuesta :

Answer:

[tex]Concentration=0.11\ mmol/L}[/tex]

Explanation:

Given that:-

Moles of the salt, [tex]NiCl_2[/tex] = 21 μmol

Also, 1 μmol = 0.001 mmol

So,

Moles = 0.021 mmol

Given that:- The volume = 200 mL

Also, 1 mL = 0.001 L

So, Volume = 0.2 L

Thus,

[tex]Concentration=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]

[tex]Concentration=\frac{0.021\ mmol}{0.2\ L}[/tex]

[tex]Concentration=0.11\ mmol/L}[/tex]

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