Answer
given,
flow from the artery = 3.5 x 10ā»ā¶ m³/s
Radius of artery = 5.80 x 10ā»Ā³m
area = Ļ R²
Ā Ā Ā Ā = Ļ x (5.8 x 10ā»Ā³)²
Ā Ā Ā Ā = 1.06 x 10ā»ā“ m²
[tex]v = \dfrac{Q}{A}[/tex]
[tex]v = \dfrac{3.5 \times 10^{-6}}{1.06 \times 10^{-4}}[/tex]
v = 0.033 m/s
b) new velocity of flow
Radius = R' = R/4
Ā A V = A' V'
 R² V = R'² V'
Ā R^2 V = (\dfrac{R}{4})^2 V'
Ā V' = 16 V
Ā V' = 16 x 0.033
Ā V' =0.528 m/s