Respuesta :
Explanation:
The given data is as follows.
       height (h) = 4.70 m,   mass = 81.0 kg
       t = 1.84 s
As formula to calculate the velocity is as follows.
      [tex]\nu[/tex] = 2gh
            = [tex]2 \times 9.8 m/s^{2} \times 4.70 m[/tex]
            = 92.12 [tex]s^{2}[/tex]
As relation between force, time and velocity is as follows.
           F = [tex]\frac{m \times \nu}{t}[/tex]
Hence, putting the given values into the above formula as follows.
         F = [tex]\frac{m \times \nu}{t}[/tex]
           = [tex]\frac{81.0 kg \times 92.12 s^{2}}{1.84 s}[/tex]
           = 4055.28 N
Thus, we can conclude that the magnitude of the average force exerted on the diver during that time is 4055.28 N.
