Determine the general form of the equation for the circle (x – 1)2 + (y + 2)2 = 3.


x2 + y2 – 2x + 4y + 2 = 0

x2 + y2 – 2x + 4y – 4 = 0

x2 + y2 – x + y + 3 = 0

x2 + y2 – x + y + 2 = 0

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Answer:

Step-by-step explanation:

(x-1)² + (y+2)² = 3

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(x-1)²

(x-1)(x-1)

x² - x - x + 1

x² - 2x + 1

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(y+2)²

(y+2)(y+2)

y²+ 2y + 2y + 4

y² + 4y + 4

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(x² - 2x + 1) + (y² + 4y + 4) = 3

x² - 2x + 1 + y² + 4y + 4 = 3

x² + y² - 2x + 4y + 1 + 4 = 3

x² + y² - 2x + 4y + 5 = 3

x² + y² - 2x + 4y + 5 - 3 = 0

x² + y² - 2 x + 4y + 2 = 0

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Answer:

x2 + y2 – 2x + 4y + 2 = 0

Step-by-step explanation:

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