Maximum number of rides Alex can go is 23
Solution:
Given that Alex mom gave him $ 45 to spend
Admission to the fair was $ 7, and each ride costs $1.50
From given question,
The amount of money spent on admission to the fair and on a number of rides which each cost $ 1.50, must be at most $ 45
"At most $ 45" means $ 45 exactly or less
Let "x" be the number of rides Alex takes up
[tex]7 + 1.50 (x) \leq 45[/tex]
[tex]1.50x + 7 \leq 45[/tex]
This is the required inequality
To find the maximum number of possible rides, solve for x
[tex]1.50x + 7 \leq 45\\\\1.50x\leq 45 - 7\\\\1.50x\leq 38\\\\x \leq 25.33[/tex]
Thus maximum number of rides he can go is 23
