Jayden ran [tex]\frac{6}{25}[/tex] of a kilometers in one minute
Solution:
Given that Angel and Jayden were at track practice
The track is two-fifth kilometers around
[tex]\text{ track length } = \frac{2}{5} \text{ kilometers}[/tex]
Angel ran 1 lap in 2 minutes
Jayden ran 3 laps in 5 minutes
To find: distance ran by Jayden in 1 minute
3 laps were run by Jayden in 5 minutes
3 laps = 5 minutes
"x" laps = 1 minute
Therefore laps run by Jayden in one minute is:
On cross multiplication we get,
5x = 3
[tex]x = \frac{3}{5}[/tex]
Therefore Jayden ran [tex]\frac{3}{5}[/tex] laps in 1 minute
Distance covered is:
Total track length = [tex]\frac{2}{5} \text{ km}[/tex]
Distance ran in 1 minute = [tex]\frac{3}{5} \times \frac{2}{5} = \frac{6}{25}[/tex]
Thus Jayden ran [tex]\frac{6}{25}[/tex] of a kilometers in one minute
Jayden ran of a kilometers in one minute
Solution:
Given that Angel and Jayden were at track practice
The track is two-fifth kilometers around
Angel ran 1 lap in 2 minutes
Jayden ran 3 laps in 5 minutes
To find: distance ran by Jayden in 1 minute
3 laps were run by Jayden in 5 minutes
3 laps = 5 minutes
"x" laps = 1 minute
Therefore laps run by Jayden in one minute is:
On cross multiplication we get,
5x = 3
Therefore Jayden ran laps in 1 minute
Distance covered is:
Total track length =
Distance ran in 1 minute =
Thus Jayden ran of a kilometers in one minute
