Answer:
30 jars of nuts worth $4 per jar must be mixed with 20 jars of nuts worth $6 per jar
Step-by-step explanation:
Let
x ----> the number of jars of nuts worth $4
y ----> the number of jars of nuts worth $6
we know that
[tex]x+y=50[/tex] ----> equation A
[tex]4x+6y=4.80(50)[/tex]
[tex]4x+6y=240[/tex] ----> equation B
Solve the system by graphing
The solution of the system of equations is the intersection point both graphs
using a graphing tool
The solution is the point (30,20)
see the attached figure
therefore
30 jars of nuts worth $4 per jar must be mixed with 20 jars of nuts worth $6 per jar
