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Below is the DNA strand template for making an mRNA needed to produce a small peptide. a.) Transcribe the sequence into mRNA. (0.5 pt.) b.) Translate the mRNA sequence into protein. (0.5 pt.) c.) Transcribe the mRNA and translate into protein with a mutant sequence that has a transition at position 11. What type of mutation does this cause

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Answer:

a) mRNA:        AUG  ACC  GGC  AAU  CAA  CUA  UAU  UGA

b) Protein: Methionine, Threonine, Glycine, Asparagine, Glutamine, Leucine, Tyrosine,  Stop.  

Explanation:

The Question was missing the DNA Strand. I have looked up the question and found this to be the DNA strand related to this question. A picture for converting codons to amino acids is also attached. A protein is simply a strand of Amino Acids.

DNA (3 to 5 sequence):

TAC    TGG   CCG    TTA    GTT   GAT    ATA    ACT

a).  Transcribing to mRNA (5 to 3 sequence):

AUG   ACC   GGC   AAU   CAA   CUA   UAU   UGA

b).  Related Amino Acids:

 1st Codon:  Methionine

2nd Codon:  Threonine

3rd Codon:  Glycine  

4th Codon:  Asparagine  

5th Codon:  Glutamine  

6th Codon:  Leucine  

7th Codon:  Tyrosine  

8th Codon:  Stop Codon

c.) DNA with Transition Mutation at Position 11 (5 to 3 sequence):

In genetics, Transition is a point mutation which converts a purine nucleotide to another i.e. A ↔ G, or a pyrimidine nucleotide to another pyrimidine i.e. C ↔ T. Hence, after transition at 11 position, T will be changed to C.

TAC    TGG   CCG    TCA    GTT   GAT    ATA    ACT

Transcribing to mRNA (5 to 3 sequence):

AUG   ACC   GGC   AGU   CAA   CUA   UAU   UGA

Related Amino Acids:

 1st Codon:  Methionine

2nd Codon:  Threonine

3rd Codon:  Glycine  

4th Codon:  Serine  

5th Codon:  Glutamine  

6th Codon:  Leucine  

7th Codon:  Tyrosine  

8th Codon:  Stop Codon

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