Respuesta :
The given question is incomplete. The complete question is as follows.
A wave has the mathematical form y = [tex](0.2 m) sin(2\pi ft - \frac{2 \pi x}{\lambda}[/tex]. What is the displacement of a particle at the origin after a time [tex]t = \frac{1}{8T}[/tex]?
Explanation:
Let us assume that at origin, x = 0 and the value of t is given as [tex]\frac{1}{8T}[/tex].
Therefore, we will calculate the value of displacement as follows.
y = [tex]0.2 \times sin[\frac{2 \pi}{T} \times \frac{1}{8}T - \frac{2 \pi}{\lambda (0)}][/tex]
= [tex]0.2 sin [\frac{\pi}{4} - 0][/tex]
= 0.1414 m
= 0.14 (approx)
Thus, we can conclude that displacement of a particle at the origin after a time [tex]t = \frac{1}{8T}[/tex] is 0.14.
