Answer:
v_2 = 972 π inch^3
Explanation:
Given data:
volume of air V_1 = 288π inc^3
radius of ball at 1 beach = r_1
radius of ball at 2nd beach = r_1 + 3
we know that [tex]V_1 = 288 \pi[/tex]
we know that volume is given as [tex]v_1 = \frac{4}{3} \pi r_1^3[/tex]
so equating both side of volume we get
[tex]288\pi = \frac{4}{3} \pi r_1^3[/tex]
r_1 = 6 inch
therefore r_2 = 9 inch
volume of air at 2nd beach [tex]v_2 = \frac{4}{3} \pi 9^3[/tex]
v_2 = 972 π inch^3
