Answer:
0.43 s
Explanation:
We have the following parameters:
Initial velocity, u = 7.4 m/s
Acceleration of gravity, g = 9.8 [tex]m/s^2[/tex]
Distance, s = 43 in + 10 ft = 1.092 m + 3.048 m = 4.14 m
Time, t = ?
Using the equation of motion [tex]s=ut +\frac{1}{2}gt^2[/tex], we have
[tex]4.14 = 7.4t + 0.5\times9.8t^2[/tex]
[tex]4.9t^2 + 7.4t - 4.14 =0[/tex]
Using the quadratic formula [tex]\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex] where a = 4.9, b = 7.4 and c = - 4.14, and solving for the positive value of t only, we have
[tex]t = 0.43[/tex] s