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Answer:
56.6 mm of Hg
Explanation:
Given that;
the diastolic blood pressure at the heart level is 80.0 mm Hg = [tex](P_0)[/tex]
height = 0.300 m
the diastolic pressure at the height of the head, which is 0.300 m above the heart can be determined using the formula
P= [tex](P_0) - (pgh)[/tex]
where; [tex](pgh)[/tex] is the hydrostatic pressure applied by the column of the liquid (Blood) of height (h) and average density [tex]p[/tex], also the g = gravitational acceleration.
the average density [tex]p[/tex] of a human blood = 1060 kg/m³
gravitational acceleration. ( g ) = 9.81 m/s²
h = 0.300 m
∴ the [tex](pgh)[/tex] = 1060 kg/m³ × 9.81 m/s² × 0.300 m
= 3119.58 Pascal (Pa)
From the standard conversion rate, 1 mm of Hg(mercury) = 133.322 Pa
∴ the amount of mm of Hg(mercury) that can be gotten from 3119.58 Pascal (Pa) will be; [tex]\frac{3119.58}{133.322}[/tex]
= 23.40 mm of Hg(mercury)
P= [tex](P_0) - (pgh)[/tex]
P= (80.0 - 23.4) mm of Hg
P= 56.6 mm of Hg
Diastolic pressure at the height of the head, which is 0.300 m above the heart is 56.6 mmHg.
Given here,
Diastolic blood pressure at the heart level = 80.0 mm Hg
0.300 m above, diastolic pressure = ?
The Diastolic pressure can be calculated using the formula
[tex]\bold {P_d = h \times g \times \rho }[/tex]
Where,
[tex]\rho[/tex] = average density of a human blood = 1060 kg/m³
g - gravitational acceleration. = 9.81 m/s²
h = Height = 0.300 m
Diastolic pressure,
= 1060 kg/m³ × 9.81 m/s² × 0.300 m
= 3119.58 Pascal (Pa)
Since, 1 mmHg = 133.322 Pa
So, 3119.58 Pascal = 23.40 mmHg
Thus ,
Pd = (80.0 - 23.4) mmHg
Pd = 56.6 mmHg
Therefore, diastolic pressure at the height of the head, which is 0.300 m above the heart is 56.6 mmHg.
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