Four ice cubes at exactly 0°C having a total mass of 53.5 g are combined with 115 g of water at 75°C in an insulated container. If no heat is lost to the surroundings, what will be the final temperature of the mixture?The specific heat capacity of water = 4.184 J/(g°C)and the standard enthalpy of fusion for water = 6.02 kJ/mol.

Respuesta :

Answer:

The final temperature of the mixture is 37.8°C

Explanation:

Standard enthalpy of fusion of water = 6.02kJ/mol = 6.02kJ/mol × 1000J/1kJ × 1mol of water/18g = 334.4J/g

Heat loss by water = heat gained by ice

mc(T1 - T2) = mL

115×4.184(75 - T2) = 53.5×334.4

75 - T2 = 17890.4/481.16

75 - T2 = 37.2

T2 = 75 - 37.2 = 37.8°C

Final temperature of mixture is 37.8°C