The density of liquid oxygen at its boiling point is 1.14 kg/Lkg/L , and its heat of vaporization is 213 kJ/kgkJ/kg . How much energy in joules would be absorbed by 2.0 LL of liquid oxygen as it vaporized? Express your answer to two significant figures and include the appropriate units.

Question

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Respuesta :

DeniceSandidge DeniceSandidge · Answer 1 · 2020-02-06T08:38:41+01:00

Answer:

heat absorbed = 4.9 × [tex]10^{5}[/tex] J

Explanation:

given data

density of liquid oxygen = 1.14 kg/L

volume = 2 L

heat of vaporization = 213 kJ/kg

solution

first we get here mass of liquid that is

mass of liquid = density × volume ......................1

mass of liquid = 1.14 × 2

mass of liquid = 2.28 kg

so here we get now heat absorbed that is

heat absorbed = mass × heat of vaporization

heat absorbed = 2.28 kg × 213 kJ/kg

heat absorbed = 485.640 kJ

heat absorbed = 4.9 × [tex]10^{5}[/tex] J