Starting from a pillar, you run 200 m east (the + x-direction) at an average speed of 5.0 m/s and then run 280 m west at an average speed of 4.0 m/s to a post. Calculate (a) your average speed from pillar to post and (b) your average velocity from pillar to post.

Respuesta :

Answer:

Total time taken=110 seconds

Total distance traveled=480m

Explanation:

First of all, we find the total time taken:

For that, we use the formula : Distance/Speed= Time

Time for part 1 : 200/5=40 seconds

Time for part 2 : 280/4=70seconds

Total time taken=110 seconds

Total distance traveled=480m

Average Speed= 480/110=4.36 m/s

Total displacement=200-280=-80m (Since this is displacement, we need to find the distance between the initial and final point. Also, I've taken east direction as positive and west as negative)

Average Velocity=-80/110=-0.72 m/s

OR 0.72m/s towards west.

Part A. The average speed, to travel a distance from pillar to the post, is  4.36 m/s.

Part B. The average velocity, to travel a distance from pillar to post, is 0.72 m/s.

Average Speed and Velocity

The total length of the path traveled by an object for a given time interval during which the motion has taken place is called the average speed of the object.

The average velocity is defined as the total change in the position of the object for the given time interval.

Given that the distance (d1) from the pillar is 200 m and the speed (s1) to cover this distance is 5 m/s. The time taken to cover the distance of 200 m is given below.

Time [tex]t_1 = \dfrac {d_1}{s_1}[/tex]

[tex]t_1 = \dfrac {200}{5}[/tex]

[tex]t_1 =40 \;\rm s[/tex]

The distance (d2) towards the post is 280 m and the speed (s2) to cover this distance is 4 m/s. The time taken to cover the distance of 280 m is given below.

Time [tex]t_2 = \dfrac {d_2}{s_2}[/tex]

[tex]t_2 = \dfrac {280}{4}[/tex]

[tex]t_2 =70 \;\rm s[/tex]

Part A

The average speed can be calculated by the total distance from pillar to post covered within the total time interval.

Total Distance [tex]d = d_1 +d_2[/tex]

[tex]d = 200+280[/tex]

[tex]d = 480 \;\rm m[/tex]

Total Time  [tex]t = t_1+t_2[/tex]

[tex]t = 40 +70[/tex]

[tex]t = 110\;\rm s[/tex]

The average speed s is given below.

[tex]s = \dfrac {480}{110}[/tex]

[tex]s = 4.36\;\rm m/s[/tex]

Hence the average speed, to travel a distance from pillar to the post, is  4.36 m/s.

Part B

The total displacement D from the pillar to the post is given below.

[tex]D = 200-280[/tex]

[tex]D = -80\;\rm m[/tex]

The displacement shows a negative sign for the direction from east to west.

The average velocity v is,

[tex]v = \dfrac {D}{t}[/tex]

[tex]v =\dfrac {-80} {110}[/tex]

[tex]v = -0.72\;\rm m/s[/tex]

Hence we can conclude that the average velocity, to travel a distance from pillar to post, is 0.72 m/s.

To know more about the speed and velocity, follow the link given below.

https://brainly.com/question/5794232.