Two tuning forks sounding together result in a beat frequency of 3 Hz. If the frequency of one of the forks is 256 Hz, what is the frequency of the other?

Respuesta :

Answer:

The other frequency is either 253Hz (the altered tuning frequency vibrates lower) or 259Hz(if the altered tuning frequency vibrates higher):

Explanation:

We have two frequencies: the tuning fork frequency  and  the altered tuning fork frequency  

F1 -----tuning fork frequency

F2-----Altered tuning fork frequency

Fbeat=3

F1=256Hz

To find the alterd tuning fork frequency:

The beat frequency of any two waves is:

Fbeat =|f1 – f2|

i.e  we have two choices

for  frequency tied to length increase (wavelength increases as length increases, therefore frequency decrease (the altered tuning frequency vibrates lower):   Fbeat = f2-f1

       F2=F1-Fbeat

     F2= 256-3

         =253Hz

For  frequency tied to length decrease wavelength increases as length increases, therefore frequency also increases(the altered tuning frequency vibrates higher) :    Fbeat = -(f2-f1)

F2= Fbeat+F1

   = 256+3

   = 259Hz

Note that a wavelength increase means a decrease of frequency because v = fλ

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