charge densities such that are equal in magnitude but opposite in sign. The difference in potential between the plates is 490 V.
(a) Is the positive or the negative plate at the higher potential?
select
the positive plate
the negative plate


(b) What is the magnitude of the electric field between the plates?
____ kV/m

Respuesta :

Answer:

a) The positive plate is at a higher potential than the negative plate.

b) Electric field between the plates = 5.76 KV/m

Explanation:

a) The positive plate is at a higher potential than the negative plate because of convention. We could define the negative plate to be "high potential." However, that convention has to be consistent. The positive plate is at the high potential, and that potential causes positive charges to flow from high potential to low potential. If we had defined the convention in the other direction, then the negative terminal would be the high potential, and that potential would cause negative charges to flow from high potential to low potential.

b) Electric field, E = potential difference across plate/distance or separation between the plates

E = V/d

V = 490V, d = 8.5cm = 0.085m

E = 490/0.085 = 5,764.706 V/m = 5.76 KV/m

Hope this helps!!!

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