Answer:
404K
Explanation:
Data given, Kinetic Energy.K.E=8.37*10^-21J
Note: as the temperature of a is increase, the rate of random movement will increase, hence leading to more collision per unit time. Hence we can say that the relationship between the kinetic energy and the temperature is a direct variation.
This relationship can be expressed as
[tex]K.E=\frac{3}{2}KT[/tex]
where K is a constant of value 1.38*10^-23
Hence if we substitute the values, we arrive at
[tex]T=\frac{2/3(8.37*10^{-21})}{1.38*10^-23}\\ T=404K[/tex]
converting to degree we have [tex]131^{0}C[/tex]
