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Bob has 60 coins consisting of quarters and dimes. The coins combined value is $13.35. How many quarters and how many dimes does he have?

Respuesta :

60x0.25=15
60x0.10=6
51x0.25=12.75
13.35-12.75
D-6
Q-51

Answer:

D + Q = 60

.10d + .25q = 13.35

.10(60+Q) + .25q= 13.35

6 + .15q = 13.35

.15q = 7.35

Q = 49

D + 49 = 60

D = 11

Bob has 49 quarters and 11 dimes.

Step-by-step explanation:

The process of substitution was used to solve this problem.

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