Answer:
[tex]C = 1/18[/tex]
Step-by-step explanation:
Remember that for a probability density function
[tex]\int_{-\infty}^{\infty } f(x) dx = 1[/tex]
Since [tex]f(x) = 0[/tex] outside [tex][0,2][/tex] we would have that
[tex]\int_{0}^{2} C(10-x) dx = 1[/tex]
Therefore
[tex]18C = 1 \\C = 1/18[/tex]