Respuesta :
3x + 7 [tex] \geq [/tex] 2
Subtract 7 from both sides
[tex]3x +7 -7 = 2-7[/tex]
[tex]3x = -5[/tex]
Divide 3 to both sides
[tex] \frac{3x}{3} = \frac{-5}{3} [/tex]
Cancel out the 3 from the left
x ≥ [tex] \frac{-5}{3} [/tex]
Subtract 7 from both sides
[tex]3x +7 -7 = 2-7[/tex]
[tex]3x = -5[/tex]
Divide 3 to both sides
[tex] \frac{3x}{3} = \frac{-5}{3} [/tex]
Cancel out the 3 from the left
x ≥ [tex] \frac{-5}{3} [/tex]
Lets do this step by step :)
1st. Subtract 7 from both sides.
3x +7 > -2
- 7 > -7 Now it cancels out on the left hand side. And we solve -2 - 7 = - 9
2nd. Now lets set up our equation again.
3x > -9
3rd. Now lets divide both sides by 3 to isolate x to be alone.
3x > -9
÷3 > ÷3 Now it cancels out on the left hand side. And we solve -9 ÷ 3 = -3
So our final answer is
x > -3
or in word form (x is greater than -3)
- have a lovely day :)
1st. Subtract 7 from both sides.
3x +7 > -2
- 7 > -7 Now it cancels out on the left hand side. And we solve -2 - 7 = - 9
2nd. Now lets set up our equation again.
3x > -9
3rd. Now lets divide both sides by 3 to isolate x to be alone.
3x > -9
÷3 > ÷3 Now it cancels out on the left hand side. And we solve -9 ÷ 3 = -3
So our final answer is
x > -3
or in word form (x is greater than -3)
- have a lovely day :)