To figure that out we will need to know the quadratic formula which is: [tex]x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }[/tex]
Since we only want to know the square root part we will solve only for this part: [tex] \sqrt{b^2-4ac} [/tex]
Now we need to list our values (a,b,c) To determine which number belongs to which letter we use the standered form equation which is : [tex]ax^2+bx+c[/tex]
And next part is super easy! We simply match up the numbers to the letters. We have: a=2 b=-2 c=-1 Next we plug in the given info into the square root: [tex] \sqrt{(-2)^2-4(2)(-1)} [/tex] Now we solve: [tex] \sqrt{(4-4(2)(-1)} [/tex] [tex] \sqrt{(4-8(-1)} [/tex] [tex] \sqrt{(4-(-8)} [/tex] [tex] \sqrt{(12)} [/tex] [tex] \sqrt{(12)} [/tex] [tex] \sqrt{(12)}=3.46 [/tex] Final answer: 3.46
