Answer:
1461460
Step-by-step explanation:
From the question given, we obtained the following data:
a = 22
Last term = T6 = 1299078
Let us find the common ratio(r)
Tn = ar^(n-1)
T6 = ar^5
1299078 = 22r^5
Divide both side by 22
r^5 = 1299078/22
r^5 = 59049
Take the fifth root of both side
r = 5√ 59049
r = 9
Now we can find the sum of the 6th term as follows
Sn = a[(r^n) — 1] / (r —1)
S6 = 22[(9^6) — 1] / 9—1
S6 = 22[(9^6) — 1] / 9—1
S6 = 22[531441 — 1] / 8
S6 = 22[531440] /8
S6 = 22 x 66430
S6 = 1461460
