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If you start rolling down this hill, your potential energy will be converted to kinetic energy. At the bottom of the hill ypu KE will be equal to your PE at the top, what is my speed at the bottom of the hill?

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opudodennis

Answer:

[tex]v=\sqrt{(2x/m)}\ \ m/s[/tex]

Explanation:

Potential Energy= Kinetic Energy

Let [tex]x[/tex] be the value of Kinetic Energy.

We know that

[tex]PE=KE=x\\x=\frac{1}{2}mv^2\\[/tex]

Make [tex]v[/tex] the subject of the formula to get speed at the bottom of the hill.

[tex]v^2=2x/m\\v=\sqrt{2x/m}[/tex]

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