a. When the ball is in flight, the acceleration would be = - 9.8 m/sec^2. The reasoning being that it is going against gravity.
b. When the ball reaches its maximum height, the velocity of the ball will be zero.
c. Let us assume the initial velocity of the ball = v1
We already know that final velocity of the ball (y) = 0 = x
Then
v1 = (1/2) * (9.8) * (1.62)
= 4.9 * 1.62
= 7.9 m/s^2
d. The velocity of the ball at maximum height is zero.
Let us assume the maximum height reached by the ball = h
Then
v^2 = - 2gh
(7.9)^2 = -2 * (-9.8) * h
62.41 = 19.6 h
h = 62.41/19.6
= 3.2 m
