we use the formula in1 y = y0 + vo t -0.5at^2 where y0 is the initial height equal to 775 ft, a is -32 ft/s2 and t is equal to 6 sec.substituting, y is equal to 307 feet which means the stone has gone down. in 2, we get the time above 775 which the stone reaches height thru 18 - 32t = 0; t is equal to 0.5625 seconds. the height above the edge is 780.0625 feet. the time going down is 6.98 seconds. The total time hence is 7.54 seconds. The velocity going down is found through 2ax = vi^2- vo^2. Substituting, 2 (32) *780.0625 = vi2 . Final velocity hence is 223.44 ft/s.
