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Using the C language, write a function that accepts two parameters: a string of characters and a single character. The function shall return a new string where the instances of that character receive their inverse capitalization. Thus, when provided with the character ’e’ and the string "Eevee", the function shall return a new string "EEvEE". Using the function with the string "Eevee" and the character ’E’ shall produce "eevee".

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ammary456

Answer:

#include <stdio.h>

void interchangeCase(char phrase[],char c){

  for(int i=0;phrase[i]!='\0';i++){

      if(phrase[i]==c){

          if(phrase[i]>='A' && phrase[i]<='Z')

              phrase[i]+=32;

          else

              phrase[i]-=32;      

      }

  }

}

int main(){

  char c1[]="Eevee";

  interchangeCase(c1,'e');

  printf("%s\n",c1);

  char c2[]="Eevee";

  interchangeCase(c2,'E');

  printf("%s\n",c2);    

}

Explanation:

  • Create a function called interchangeCase that takes the phrase and c as parameters.
  • Run a for loop that runs until the end of phrase and check whether the selected character is found or not using an if statement.
  • If the character is upper-case alphabet, change it to lower-case alphabet and otherwise do the vice versa.
  • Inside the main function, test the program and display the results.

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