Respuesta :
Dissolving 0.729 mol NaCl in 2530 mL of water yields a solution with 2.88M concentration.
Explanation:
The moles of NaCl given will be dissolved and volume will be made with given data will give molarity.
The units for molarity are moles/litre, so the volume given in ml will be converted to litres by dividing it with 1000.
data given:
number of moles of NaCl = 0.729 moles
volume of the solution = 2530 ml or 2.53 litre
To calculate the concentration of the solution the formula used is:
molarity = [tex]\frac{0.729}{2.530}[/tex]
= 0.288 M
The concentration or molarity of the solution OF NaCl is 2.88M
Dissolving 0.729 mol NaCl in 2530 mL of water yields a solution with "0.288 mol per liter"
Explanation:
In order to estimate the concentration of a solution in molarity, then the total number of moles of the solute is divided by the total volume of the solution. The term is represented as M and unit is mol/L.
Here,
The total number of moles of solute is = 0.729 mol NaCl
The total volume of the water used here is = 2530 mL water
The given formula is : [tex]Molarity(M) = \frac{n}{V}[/tex]
⇒ [tex]Molarity(M) = \frac{n}{V}(1000)[/tex] { If V is in ml }
⇒ [tex]Molarity(M) = \frac{0.729}{2530}(1000)[/tex]
⇒ [tex]Molarity(M) =0.000288(1000)[/tex]
⇒ [tex]Molarity(M) =0.288molL^{-1}[/tex]
Therefore, dissolving 0.729 mol NaCl in 2530 mL of water yields a solution with concentration of [tex]0.288M[/tex].
