Respuesta :

dalendrk
f(x) = x² + 2x - 1

f(2) = 2² + 2 · 2 - 1 = 4 + 4 - 1 = 7
f(-2) = (-2)² + 2 · (-2) - 1 = 4 - 4 - 1 = -1
f(3) = 3² + 2 · 3 - 1 = 9 + 6 - 1 = 14
f(-3) = (-3)² + 2 · (-3) - 1 = 9 - 6 - 1 = 2

The range = {-1; 2; 7; 14}

Answer:

(2,7) ,  (-2,-1) , (3,14) , (-3,2)

Step-by-step explanation:

Given : Function [tex]f(x)=x^2+2x-1[/tex]

To find : Match the range of the function to its domain ?

Solution :

Domain is x and range is y,

We substitute the domain values 2, -2, 3, -3 and find y,

At x=2

[tex]f(2)=(2)^2+2(2)-1[/tex]

[tex]f(2)=4+4-1[/tex]

[tex]f(2)=7[/tex]

i.e. (2,7)

At x=-2

[tex]f(-2)=(-2)^2+2(-2)-1[/tex]

[tex]f(-2)=4-4-1[/tex]

[tex]f(-2)=-1[/tex]

i.e. (-2,-1)

At x=3

[tex]f(3)=(3)^2+2(3)-1[/tex]

[tex]f(3)=9+6-1[/tex]

[tex]f(3)=14[/tex]

i.e. (3,14)

At x=-3

[tex]f(-3)=(-3)^2+2(-3)-1[/tex]

[tex]f(-3)=9-6-1[/tex]

[tex]f(-3)=2[/tex]

i.e. (-3,2)

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