Respuesta :

altavistard

Answer:

log3 {c/2}    

Step-by-step explanation:

Addiing two logs together is equivalent to multiplying their arguments.

Thus,

log3(6c) + log3 1/12 = log3 6*c*[1/12], or log3 ( log3 [6c][1/12] ).

This simplifies to   log3 {c/2}            because 6c(1/12) = c/2

fangzghostwolf

Answer: the answer is log3(c/2)

Step-by-step explanation:

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