Answer:
Option 1. 25g Al x 1mol Al/26.982g Al x 2mol Al₂O₃/ 4mol Al
Explanation:
The equation for the reaction is given below:
4Al + 3O₂ → 2Al₂O₃
Molar Mass of Al = 26.982g/mol
Mass of Al = 25g
The number of mole in 25g of Al can be expressed as:
25g of Al = 25g x 1 mol / 26.982g
From the balanced equation above,
4 mol of Al produced 2 moles of Al₂O₃.
Therefore, 25g of Al (25g x 1 mol / 26.982g) will produce =
25g Al x 1mol Al/26.982g Al x 2mol Al₂O₃/ 4mol Al
