Answer:
[tex]t=\frac{11.7-12}{\frac{0.2}{\sqrt{25}}}=-7.5[/tex]
Step-by-step explanation:
Information given
[tex]\bar X=11.7[/tex] represent the sample mean of amount of liquid
[tex]s=0.2[/tex] represent the standard deviation
[tex]n=25[/tex] sample size
[tex]\mu_o =12[/tex] represent the value that we want to check
t would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value for the test (variable of interest)
System of hypothesis
We want to verify if the true mean for the amount of liquid is lower than 12 ounces, and the hypothesis are given by:
Null hypothesis:[tex]\mu \geq 12[/tex]
Alternative hypothesis:[tex]\mu < 12[/tex]
The statistic is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
Replacing we got:
[tex]t=\frac{11.7-12}{\frac{0.2}{\sqrt{25}}}=-7.5[/tex]