Answer:
8 square units
Step-by-step explanation:
We are given that
[tex]u=-4i+4k[/tex]
[tex]v=2i[/tex]
We have to find the area of parallelogram.
We know that area of parallelogram
Area of parallelogram=[tex]\mid u\times v\mid[/tex]
[tex]u\times v=\begin{vmatrix}i&j&k\\-4&0&4\\2&0&0\end{vmatrix}[/tex]
[tex]u\times v=-j(-8)=8j[/tex]
[tex]\mid u\times v\mid=\sqrt{(8)^2}=8[/tex]
Area of parallelogram=8 square units
Hence, the area of parallelogram=8 square units
