Answer:
The angle of incidence is  [tex]\theta_i =42.6^o[/tex]
Explanation:
The diagram for this question is shown on the first uploaded image
From the question we are told that
  The distance between the mirror and the wall is  [tex]a = 33.7 cm[/tex]
  The height of the above the mirror is  [tex]b = 36.7 cm[/tex]
Generally the angle which the reflected ray make with the mirror is mathematically evaluated as
       [tex]\alpha =tan ^{-1} (\frac{b}{a})[/tex]
substituting values
       [tex]\alpha = tan ^{-1}( \frac{36.7}{33.7})[/tex]
      [tex]\alpha =47.4^o[/tex]
From the diagram we can deduce that  the angle of incidence is
       [tex]\theta_i = 90 - \alpha[/tex]
So      [tex]\theta_i = 90 - 47.4[/tex]
       [tex]\theta_i =42.6^o[/tex]
