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Given: y=x^2-4x-12

A.) determine the roots/zero
(By factoring & setting the answer equal to zero)

B.) use h=-b/2a to get vertex

Respuesta :

wegnerkolmp2741o

Answer:

see below

Step-by-step explanation:

y=x^2-4x-12

Set equal to 0 to find the zeros

0 =x^2-4x-12

Factor.  What 2 numbers multiply to -12 and add to -4

-6*2 = -12  

-6+2 = -4

0= (x-6) (x+2)

Using the zero product property

0=x-6         0 = x+2

x=6            x = -2

zeros: -2,6

Vertex

h = -b/2a = - (-4)/ 2(1) = 4/2 = 2

OR  Average the roots  (-2+6)/2 = 4/2 =2

The y coordinate is found by substituting into the equation

y = (2)^2 -4(2) -12

y = 4-8-12

y =-16

vertex : (2, -16)

amna04352

Answer:

x = -2, 6

Vertex: (2,-16)

Step-by-step explanation:

x² - 4x - 12

x² - 6x + 2x - 12

x(x - 6) + 2(x - 6)

(x - 6)(x + 2) = 0

x = -2, 6

h = -(-4)/2

h = 4/2

h = 2

k = 2² - 4(2) - 12

k = 4 - 8 - 12

k = -16

Vertex: (2,-16)

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