Answer:
The uncertainty the in position is [tex]\delta s = 0.4051 m[/tex]
Explanation:
From the question we are told
The planck's constant is [tex]h = 0.70 \ J \cdot s[/tex]
The mass of the baseball is [tex]m = 0.55kg[/tex]
The velocity of the baseball [tex]v_b = 22 m/s[/tex]
The uncertainty in [tex]\delta v = 0.5 m/s[/tex]
Generally the uncertainty of momentum is
[tex]\delta p = m \delta v[/tex]
substituting values
[tex]\delta p = 0.275 \ kg m/s[/tex]
The uncertainty position is mathematically represented as
[tex]\delta s = \frac{h}{2 \p \delta p }[/tex]
substituting values
[tex]\delta s = \frac{0.70}{2 * 3.142 * 0.275 }[/tex]
[tex]\delta s = 0.4051 m[/tex]
