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03-06-2020
Chemistry

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What is the molarity of 0.945 L of a solution that contains 0.227 moles of Fe(NO3)3?

Respuesta :

03-06-2020

Answer:

0.2402 M

Explanation:

0.945 L sol contains = 0.227 moles

1 L sol will contain = (0.227/0.945)*1 = 0.2402 moles

Molarity = 0.2402 moles/L or M

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