Answer:
a. 165.5 V
b. 7.78 A
Explanation:
Here is the complete question
The RMS potential difference of an AC household outlet is 117 V. a) What is the maximum potential difference across a lamp connected to the outlet? b) If the RMS current through the lamp is 5.5 A, what is the maximun current through the lamp.
Solution
a. The maximum potential difference across the lamp V₀ = √2V₁ where V₁ = rms value of potential difference = 117 V
V₀ = √2V₁ = √2 × 117 V = 165.5 V
b. The maximum current through the lamp I₀ = √2I₁ where I₁ = rms value of current = 5.5 A
V₀ = √2V₁ = √2 × 5.5 A = 7.78 A
