Pls solve the 6th one
Answer:
The smallest square number that is divisible by 2, 3, and 5.
=> That number is A that has form:
A = 2 x 3 x 5 x k (with 2, 3, and 5 are prime numbers, and k is arbitrary positive integer)
Because A is a square number, k should have form of 2 x 3 x 5 x a^2
with a is the smallest positive integer (to make sure A is smallest)
=> select a = 1
=> k = 2 x 3 x 5 x 1^2 = 2 x 3 x 5
=> A = 2 x 3 x 5 x k = 2 x 3 x 5 x 2 x 3 x 5 = 900
Hope this helps!
:)