Answer:
Hello
Here's the answer:
2x^2 + 5x + 2 = 0\\ 2x^2+4x+x+2=0\\ 2x(x+2)+1(x+2)=0\\ (2x+1)(x+2)=0\\ x=-\frac{1}{2} \vee x=-2
x^2-4x+1=0\\ x^2-4x+4-3=0\\ (x-2)^2=3\\ x-2 =\sqrt3 \vee x-2=-\sqrt3\\ x=2+\sqrt3 \vee x=2-\sqrt3
Step-by-step explanation:
