Answer:
a
The volume charge density is [tex]\rho = nq[/tex]
b
The surface charge density is [tex]\sigma = n^{\frac{2}{3} } q[/tex]
Explanation:
From the question we are told that
The radius is R
The length is L
The velocity is v
The number of ions per unit volume is n
The charge is q
The thickness of the cylinder surface is [tex]n^{\frac{1}{3} }[/tex]
The volume charge density is mathematically represented as
[tex]\rho = nq[/tex]
The surface charge density is mathematically represented as
[tex]\sigma = \rho n^{\frac{1}{3} }[/tex]
substituting for [tex]\rho[/tex]
[tex]\sigma = n * n^{\frac{1}{3} } q[/tex]
[tex]\sigma = n^{\frac{2}{3} } q[/tex]
