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A human expedition lands on an alien moon. One of the explorers is able to jump a maximum distance of 16.0 m with an initial speed of 2.90 m/s. Find the gravitational acceleration on the surface of the alien moon. Assume the planet has a negligible atmosphere. (Enter the magnitude in m/s2.)

Respuesta :

Answer:

Gravitational acceleration (g) = 0.4205 m/s²

Explanation:

Given:

Distance (R) = 20 m

Initial speed (u) = 2.90 m/s

Find:

Gravitational acceleration (g)

Computation:

⇒ Distance (R) = [Initial speed (u)]²/ Gravitational acceleration (g)

⇒ Gravitational acceleration (g) =  [Initial speed (u)]² / Distance (R)

⇒ Gravitational acceleration (g) = 2.90 ² / 20

⇒ Gravitational acceleration (g) = 8.41 / 20

⇒ Gravitational acceleration (g) = 0.4205 m/s²

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