PLEASE HELP, you have to write the equation in y=Mx+b form but you have to also pay attention to the scale of the graph
Answer:
y = (1/8)x + 23
Explanation:
Given:
The equation of line y = M*x + b
This line pass (0, 23) and (40, 28)
Solve:
23 = M*0 + b
28 = M*40 + b
From 1st equation:
=> b = 23
Subtract 1st equation from 2nd equation:
5 = M*40
=> M = 5/40 = 1/8
The equation of line:
=> y = (1/8)x + 23
Hope this helps!
:)