Respuesta :
Answer:
-3/2,collinear.
Step-by-step explanation:
slope of PQ=(0-3)/(2-0)=-3/2
eq. of line PQ is
y-3=-3/2(x-0)
y-3=-3/2 x
or2y-6=-3x
or 3x+2y=6
if R(4,-3) lies on it,then
3(4)+2(-3)=6
12-6=6
or 6=6
which is true.
Hence points P,Q,R are collinear.
and line has aslope=-3/2
