DER2005
DER2005 DER2005
  • 05-06-2020
  • Mathematics
contestada

[tex]\sqrt{512k^{2} }[/tex] help please!!
[tex]\sqrt{448x^{3} }[/tex]

Respuesta :

meredith48034
meredith48034 meredith48034
  • 05-06-2020

Answer:

Step-by-step explanation:

[tex]\sqrt{256*2*k*k} = 16k\sqrt{2} \\\sqrt{448x^{3} } = \sqrt{64*7*x*x^{2}}=8x \sqrt{7x}[/tex]

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