A new outdoor rec center is being built in hardford. The perimeter of the rectangular playing field is 258 yards. the length of the field is 9 yards less than double the width. Whatre the dimensions of the playing field?

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05-09-2016
Mathematics

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A new outdoor rec center is being built in hardford. The perimeter of the rectangular playing field is 258 yards. the length of the field is 9 yards less than double the width. Whatre the dimensions of the playing field?

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texaschic101 texaschic101 · Answer 1 · 2016-09-05T05:19:17+02:00

texaschic101 texaschic101

05-09-2016

P = 2(L + W)
P = 258
L = 2W - 9

258 = 2(2W - 9 + W)
258 = 2(3W - 9)
258 = 6W - 18
258 + 18 = 6W
276 = 6W
276/6 = W
46 = W <=== here is the width

L = 2W - 9
L = 2(46) - 9
L = 92 - 9
L = 83 <== here is the length

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