A circle has its center at (-2, 5) and a radius of 4 units. What is the equation of the circle? Answer choices:
(A) (x + 2)2 + (y - 5)2 = 16
(B) (x + 2)2+ (y + 5)2= 16
(C) (x + 2)2+(y - 5)2 = 4
(D) (x - 2)2+(y + 5)2 = 4

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HomertheGenius HomertheGenius · Answer 1 · 2016-09-13T21:40:44+02:00

The equation of the circle:
( x - h )² + ( y - k )² = r²;
h = - 2, k = 5, r = 4
Answer:
A ) ( x + 2 )² + ( y - 5 )² = 16

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athleticregina athleticregina · Answer 2 · 2019-02-25T07:21:32+01:00

Answer:

option (a) is correct.

The equation of a circle has its center at (-2, 5) and a radius of 4 units. is [tex](x+2)^2+(y-5)^2=16[/tex]

Step-by-step explanation:

Given : A circle has its center at (-2, 5) and a radius of 4 units.

We have to choose the correct equation representing this given circle.

The general equation of circle with center (h , k) and radius 'r' is given by equation [tex](x-h)^2+(y-k)^2=r^2[/tex]

For the given circle with center at (-2, 5) and a radius of 4 units.

that is h = -2 , k = 5 and r = 4 , we have,

[tex](x-h)^2+(y-k)^2=r^2[/tex] substitute, we have,

[tex](x-(-2))^2+(y-5)^2=(4)^2[/tex]

Simplify , we get,

[tex](x+2)^2+(y-5)^2=16[/tex]

Thus, option (a) is correct.

The equation of a circle has its center at (-2, 5) and a radius of 4 units. is [tex](x+2)^2+(y-5)^2=16[/tex]