Answer:
15
Step-by-step explanation:
d = 5 for PQ
For:
(X1, Y1) = (0, 0)
(X2, Y2) = (5, 0)
finding distance between two points
d=√(5−0)^2+(0−0)^2
d=√(5)^2+(0)^2
d=√25+0
d=√25
d=5
for RS d=3
d = 3
For:
(X1, Y1) = (3, 2)
(X2, Y2) = (0, 2)
d=√(0−3)^2+(2−2)^2
d=√(−3)^2+(0)^2
d=√9+0
d=3
Area= length * width
Area=3*5=15
